Okie, unable to find the formula and I’ve long forgotten my trigonometry. I added a MI fixed front/rear on a rifle, 16", excessive right windage(on rear) to get zero at 50. I didn’t notice at the range that the rail was off at the receiver, loosened and aligned it when home. It appeared to have maybe about .050-.062" right cant. The front is back enough to allow a M300 light at 12:00.
Curious of what that would equate to at 50? I hope to check Friday and hope that corrects the issue before I look further.
Oh-“excessive” the rear aperture was close to the right ear. At mechanical center, I was roughly 5" left at 50.
Great! yes, 15" would be about right on the radius. I’m guessing on the shift of the sight with the rail being turned slightly. If that holds true, then I shouldn’t be far from center on the rear. My back up plan is to remove material from the front sight, right side where it contacts the rail angle.
I misunderstood something when I first saw your post. Re-reading with the benefit of this morning’s coffee, I now realize that you had a handguard that was twisted to where its rail was misaligned with the receiver’s rail by .050 — .062”. If so, the offset of the front sight would have been greater than that amount because it’s farther from the axis of rotation, roughly double.